This is geometric: E = 20 × (0.95)^t
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- Initial inefficiency: 20%. Each hour, 5% of the current inefficiency is reduced. So inefficiency follows:
- after 1 hr: 20 × 0.95 = 19
- after 2 hr: 19 × 0.95 = 18.05
- Solve: 20 × (0.95)^t < 5 → (0.95)^t < 0.25
- Take log: t × log(0.95) < log(0.25) → t > log(0.25)/log(0.95) ≈ (−1.3863)/(−0.05129) ≈ <<1.3863/0.05129≈27.03>>27.03
- So t = 28 full hours.
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