Then a + b + c = 1.2 → 0.05 + 0.45 + c = 1.2 → c = 0.7
["Understanding the Equation: How 0.05 + 0.45 + c = 1.2 Leads to c = 0.7", "When working with algebraic equations, careful substitution and simplification are key to arriving at the correct solution. One illustrative example is the equation transformation:\nIf ( a + b + c = 1.2 ) and knowing ( a = 0.05 ), ( b = 0.45 ), then what is the value of c?", "Let’s break down the steps clearly to follow how ( c = 0.7 ) is derived.", "---", "### Starting from the Given Equation:\n[\na + b + c = 1.2\n]", "### Step-by-step Substitution:\nSubstitute the known values ( a = 0.05 ) and ( b = 0.45 ) into the equation:\n[\n0.05 + 0.45 + c = 1.2\n]", "### Simplify the Known Values:\nAdd ( a ) and ( b ):\n[\n0.05 + 0.45 = 0.50\n]\nSo the equation becomes:\n[\n0.50 + c = 1.2\n]", "### Solve for ( c ):\nSubtract 0.50 from both sides:\n[\nc = 1.2 - 0.50\n]\n[\nc = 0.70\n]", "---", "### Final Answer:\n[\n\boxed{c = 0.7}\n]", "---", "### Why This Equation Matters\nEquations like ( a + b + c = 1.2 ) often appear in financial modeling, probability calculations, or resource allocation, where total values must sum to a fixed quantity. In this case, once two components ( a ) and ( b ) are known, solving for ( c ) becomes straightforward—demonstrating the power of substitution in algebra.", "This simple yet essential algebraic technique ensures clarity and accuracy, critical for both academic and real-world problem solving.", "---", "Keywords for SEO:\n- How to solve for c in a + b + c = 1.2\n- Step-by-step algebra equation solution\n- Steps to find c given a + b = known values\n- Algebraic equation simplification tutorial\n- Solve linear equations in one variable", "Optimized for search engines with technical clarity and instructional value."]
