Subtract from (3):

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• $ p(3) = 27a + 9b + 3c + d = 31 \Rightarrow 27a + 9b + 3c = 29 $
• From (2): $ a + b + c = 3 $
• Multiply by 2: $ 2a + 2b + 2c = 6 $
• Multiply (2) by 3: $ 3a + 3b + 3c = 9 $
• Subtract from (4):
• Now from (5): $ b = 2 - 3a $

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