Solución: Calcula la probabilidad paso a paso.
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- P = \frac{\binom{6}{2} \times \binom{9}{2}}{\binom{15}{4}} = \frac{15 \times 36}{1365} = \frac{540}{1365} = \frac{36}{91}
- \boxed{\dfrac{36}{91}}
- Pregunta: Hay 3 fichas naranjas, 5 fichas moradas y 4 fichas plateadas en una bolsa. Si se extraen dos fichas al azar sin reemplazo, ¿cuál es la probabilidad de que ambas sean moradas?
- Número total de fichas: \( 3 + 5 + 4 = 12 \)
- Número de formas de extraer 2 fichas moradas de 5:
- \binom{5}{2} = 10
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