Question: Expand the product $ (x^2 - 3x + 2m)(x^2 - 3x + 5m) $ and simplify.

Question: Expand the product $ (x^2 - 3x + 2m)(x^2 - 3x + 5m) $ and simplify.

["Expanding and Simplifying the Product: $ (x^2 - 3x + 2m)(x^2 - 3x + 5m) $", "When working with polynomial multiplication, understanding how to expand expressions like $ (x^2 - 3x + 2m)(x^2 - 3x + 5m) $ is essential for solving equations, simplifying algebraic forms, and advancing in calculus or polynomial modeling. In this article, we will explore how to expand and simplify the given product step-by-step, providing clear insight into the algebraic process.", "---", "### Understanding the Structure", "The expression is a product of two quadratic trinomials:", "$$\n(x^2 - 3x + 2m)(x^2 - 3x + 5m)\n$$", "Both factors share the common quadratic-like structure $ (x^2 - 3x) $, with the constant terms differing: $ 2m $ and $ 5m $. This similarity allows us to treat the expression analogously to multiplying $ (A + B)(A + C) $ where $ A = x^2 - 3x $, $ B = 2m $, and $ C = 5m $.", "---", "### Step 1: Use the distributive property (FOIL analogs for polynomials)", "We apply the distributive law: multiply each term in the first factor by each term in the second.", "Let:", "- $ A = x^2 - 3x $\n- $ B = 2m $\n- $ C = 5m $", "Then:", "$$\n(x^2 - 3x + 2m)(x^2 - 3x + 5m) = (A + B)(A + C)\n$$", "Expanding:", "$$\n= A(A + C) + B(A + C) = A^2 + AC + BA + BC = A^2 + A(C + B) + BC\n$$", "Now substitute back $ A = x^2 - 3x $, $ B = 2m $, $ C = 5m $:", "$$\n= (x^2 - 3x)^2 + (x^2 - 3x)(5m + 2m) + (2m)(5m)\n$$", "---", "### Step 2: Expand each term", "#### Expand $ (x^2 - 3x)^2 $", "$$\n(x^2 - 3x)^2 = x^4 - 2 \cdot x^2 \cdot 3x + (3x)^2 = x^4 - 6x^3 + 9x^2\n$$", "#### Expand $ (x^2 - 3x)(7m) $", "$$\n(x^2 - 3x)(7m) = 7m(x^2 - 3x) = 7mx^2 - 21mx\n$$", "#### Multiply the constant terms:", "$$\n(2m)(5m) = 10m^2\n$$", "---", "### Step 3: Combine all terms", "Now substitute each expanded piece back:", "$$\nx^4 - 6x^3 + 9x^2 + (7mx^2 - 21mx) + 10m^2\n$$", "Group like terms:", "- $ x^4 $: $ x^4 $\n- $ x^3 $: $ -6x^3 $\n- $ x^2 $: $ 9x^2 + 7mx^2 = (9 + 7m)x^2 $\n- $ x $: $ -21mx $\n- Constant: $ 10m^2 $", "---", "### Final simplified expression", "$$\n\boxed{x^4 - 6x^3 + (9 + 7m)x^2 - 21mx + 10m^2}\n$$", "---", "### Why This Expansion Matters", "- Factoring Insight: The original form reveals a pattern well-suited for algebraic manipulation without full expansion, but knowing how to expand aids in verifying factorizations.\n- Quadratic in disguise: The inner structure $ x^2 - 3x $ hints at a substitution $ u = x^2 - 3x $, simplifying to $ (u + 2m)(u + 5m) = u^2 + 7mu + 10m^2 $, confirming our result post-expansion.\n- Application: Polynomial expansions are crucial in calculus (e.g., Taylor expansions), physics modeling, and control systems where nonlinear terms combine predictably.", "---", "Conclusion", "Expanding $ (x^2 - 3x + 2m)(x^2 - 3x + 5m) $ produces the simplified quartic polynomial:", "$$\nx^4 - 6x^3 + (9 + 7m)x^2 - 21mx + 10m^2\n$$", "This process demonstrates how shared structure in polynomials allows for efficient computation and deepens understanding of algebraic symmetry and simplification. Whether for homework, exam prep, or advanced study, mastering such expansions strengthens foundational mathematics skills.", "---", "### SEO Keywords:\n- Expand $ (x^2 - 3x + 2m)(x^2 - 3x + 5m) $\n- Simplify polynomial product\n- Algebraic expansion tutorial\n- Polynomial multiplication steps\n- Factoring and expanding quadratic binomials\n- Solve $ (x^2 - 3x + 2m)(x^2 - 3x + 5m) $\n- Algebraic simplification guide", "---", "Optimize your learning with structured practices—expanding and simplifying products like this empowers deeper mastery of algebra and its applications."]

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