Odd prime choice: 2
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- For Case 2:
- Choose 2 positions for the two prime rolls: $ \binom{4}{2} = 6 $
- Assign one prime as 2, one as odd (3 or 5): 2 ways (which is which)
- Non-primes: one must be odd (1), one even (4 or 6): 2 choices
- → Total: $ 6 \times 2 \times 2 \times 2 = 48 $? Wait: 6 (position pairs) × 2 (order: which prime is 2) × 2 (odd choice) × 2 (even choice) = $ 6 \times 2 \times 2 \times 2 = 48 $
- But earlier Case 1 gave 24 → total valid: 24 + 48 = 72
