Now divide $8112$ by $12$:
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- 2Question: What is the remainder when $2025 + 2027 + 2029 + 2031$ is divided by 12?
- Solution: First, compute the sum:
- + 2027 + 2029 + 2031 = (2025 + 2031) + (2027 + 2029) = 4056 + 4056 = 8112.
- \div 12 = 676 ext{ exactly, since } 12 imes 676 = 8112.
- Thus, the remainder is $0$.
- Therefore, the remainder is $oxed{0}$.
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