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/ k \equiv 4 \pmod{7} \
k \equiv 4 \pmod{7} \
February 22, 2026
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Solution: We solve the system of congruences:
egin{cases}
k \equiv 3 \pmod{5} \
k \equiv 2 \pmod{9}
We apply the Chinese Remainder Theorem step by step.
First, solve the first two congruences:
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