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- After day 3: 4,500,000 × 0.75 = 3,375,000
- #### 3,375,000**Question: A herpetologist studying reptile population dynamics models the growth of a lizard population with a quadratic polynomial \( h(x) \) such that \( h(0) = 3 \), \( h(1) = 8 \), and \( h(2) = 15 \). Find \( h(x^2 + 2) \).
- To find the quadratic polynomial \( h(x) = ax^2 + bx + c \), we use the given conditions:
- \( h(1) = 8 \) gives us \( a(1)^2 + b(1) + 3 = 8 \) which simplifies to \( a + b + 3 = 8 \). Thus, \( a + b = 5 \).
- \( h(2) = 15 \) gives us \( a(2)^2 + b(2) + 3 = 15 \) which simplifies to \( 4a + 2b + 3 = 15 \). Thus, \( 4a + 2b = 12 \).
- Now, solve the system of equations: