\frac{7}{5} = \frac{21}{x}

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• The ratio of capsid protein A to capsid protein B is \(7:5\). This means for every 7 molecules of protein A, there are 5 molecules of protein B.
• Given 21 molecules of protein A, we find the corresponding number of protein B molecules.
• Let the number of protein B molecules be \(x\). Then:
• 7x = 21 \times 5 = 105
• x = \frac{105}{7} = 15
• There are 15 molecules of protein B. The total number of molecules is:

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