\frac{140}{6} + c = -4 \implies \frac{70}{3} + c = -4

["# Solving the Equation: (\frac{140}{6} + c = -4 \implies \frac{70}{3} + c = -4)", "Understanding how to solve and interpret linear equations is essential for mastering algebra. This article breaks down the equation (\frac{140}{6} + c = -4), simplifies it to (\frac{70}{3} + c = -4), and explains step-by-step how to find the value of the unknown variable (c). Whether you're a student learning algebra basics or someone refining your math skills, this guide will clarify the process with clear explanations and practical steps.", "---", "## Step 1: Simplify the Fraction (\frac{140}{6})", "Before solving for (c), simplify the constant term (\frac{140}{6}):", "[\n\frac{140}{6} = \frac{70 \ imes 2}{3 \ imes 2} = \frac{70}{3}\n]", "So, the original equation\n[\n\frac{140}{6} + c = -4\n]\nsimplifies neatly to\n[\n\frac{70}{3} + c = -4\n]", "---", "## Step 2: Isolate the Variable (c)", "To solve for (c), subtract (\frac{70}{3}) from both sides:", "[\nc = -4 - \frac{70}{3}\n]", "Now, write (-4) as a fraction with denominator 3:", "[\n-4 = -\frac{12}{3}\n]", "Now substitute back:", "[\nc = -\frac{12}{3} - \frac{70}{3} = -\frac{82}{3}\n]", "---", "## Step 3: Final Solution", "The solution to the equation is:", "[\nc = -\frac{82}{3}\n]", "This means the variable (c) equals (-\frac{82}{3}), which is approximately (-27.33) in decimal form.", "---", "## Why This Equation Matters", "Linear equations form the foundation of algebra and appear in countless real-world problems, including budgeting, physics, economics, and computer science. Mastering steps like simplifying fractions and isolating variables helps build confidence and clarity in more complex mathematical challenges ahead.", "---", "## Conclusion", "Starting with (\frac{140}{6} + c = -4), we simplified to (\frac{70}{3} + c = -4), then solved for (c) by subtracting (\frac{70}{3}) from both sides. The precise solution—(c = -\frac{82}{3})—is not only correct but also illustrates key algebraic principles. Keep practicing with simplification and variable isolation to strengthen your math foundation!", "---", "Keywords for SEO:\nlinear equation solution, solve (\frac{140}{6}), simplify fractions in algebra, isolate variable (c), algebra step-by-step guide, solve linear equations 2024, algebra practice problems, rational number equations, solving for (c) algebraically", "Meta Description:\nLearn how to solve (\frac{140}{6} + c = -4) step-by-step, simplifying (\frac{140}{6}) to (\frac{70}{3}) and finding (c = -\frac{82}{3}). Perfect for mastering algebra fundamentals."]