But test $ 1\cdot2\cdot3\cdot4 = 24 $ → divisible by 24
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- Additionally, among four consecutive numbers, one is divisible by 4, and another even → total $ 2^3 = 8 $
- Also, one is divisible by 4 and another even → but already included
- Moreover, in every set of 4 consecutive integers, one is divisible by 4, one by 2 (not divisible by 4), and one by 3 → so minimum $ 2^3 \cdot 3 = 24 $
- $ 2\cdot3\cdot4\cdot5 = 120 $, divisible by 24
- $ 3\cdot4\cdot5\cdot6 = 360 $, $ 360 / 24 = 15 $
- Is 48 always a divisor? $ 24 $ is not divisible by 48 → no
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