After 20% shortage, effective component pool: 2448 * 0.80 = 1958.4 → Less than needed.
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- Let’s assume initial component stock allows for *X* units before delay. But per hour, after slowdown: 204 units require 204 * 3 = 612 components per hour.
- But if supply drops by 20%, capacity is further reduced. However, production slowdown is already applied.
- The key is: with 816 units attempt, but components limited: suppose original component stock supports 816 * 3 = 2448 components.
- But under 15% slower operation, only 816 units can be assembled.
- Assuming components are sufficient or replenished, production is limited by time: 816 units.
- But the question asks how many **complete** units can be produced — assuming components are not the limiting factor during operation, and production rate is based on functionality.
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