3n + 4p = 7.80 \quad \text{(1)}

3n + 4p = 7.80 \quad \text{(1)}

Understanding the Linear Equation: 3n + 4p = 7.80

When solving equations like 3n + 4p = 7.80, we dive into the foundational world of algebra, unlocking the relationship between two variables — typically representing cost, quantity, or rate. This equation serves as a powerful model in various real-world contexts such as economics, budgeting, and business pricing.


What Is the Equation 3n + 4p = 7.80?

The equation 3n + 4p = 7.80 is a linear Diophantine expression involving two variables:

  • n often represents the quantity of one item, such as a unit of product A, priced at $3 per unit.
  • p stands for the quantity of another item, say product B, at $4 per unit.

The right-hand side, 7.80, is the total cost — the sum of costs from buying n units of product A and p units of product B.

In short: Total cost = (price per unit × quantity) for both products = $7.80


Solving for One Variable

To make sense of this equation, solving for one variable in terms of the other clarifies relationships within the system.

Solving for p: Start from equation (1): 3n + 4p = 7.80

Subtract 3n from both sides: 4p = 7.80 – 3n Then divide both sides by 4: p = (7.80 – 3n) / 4

This formula lets you compute the value of p for any given n, as long as the result is a non-negative real number if quantities must be non-negative.


Practical Applications

  1. Budgeting and Shopping Imagine buying oranges (n) at $3 per kg and apples (p) at $4 per kg. With a fixed budget of $7.80, this equation helps determine how many of each fruit you can buy.

  2. Cost Analysis in Business In manufacturing, the equation models total production costs based on units of two raw materials or labor tiers.

  3. Market Equilibrium Studies Social scientists and economists use similar equations to model supply-demand scenarios where two variables influence a known total cost or revenue.


Finding Integer Solutions

For real-life scenarios where only whole units can be purchased, 3n + 4p = 7.80 poses a special challenge — full solutions in integers (wholesale buying, inventory units) rather than decimals.

To find integer solutions accurately:

  • Rearrange equation (1): 3n = 7.80 – 4p
  • Test small whole-number values of p until 7.80 – 4p is divisible by 3 and produces a non-negative n.

Example: Try p = 1 → 3n = 7.80 – 4(1) = 3.80 → n = 3.80 / 3 ≈ 1.27 (not integer)

Try p = 0.50 → 3n = 7.80 – 4(0.50) = 5.80 → n ≈ 1.93 (still not ideal)

A better approach is to clear decimals: Multiply entire equation 3n + 4p = 7.80 by 10:

30n + 40p = 78

Now work with integers: 15n + 20p = 39

Try small integer values for n and p that satisfy this equation — tools like elimination or substitution make finding exact cost combinations possible.


Conclusion

The equation 3n + 4p = 7.80 is a simple yet effective representation of a real-world linear relationship involving two quantities and their costs. Whether used in budgeting, pricing, or data modeling, understanding how to interpret and solve this equation empowers better decision-making. For practical, whole-number solutions, adjusting or scaling the equation appropriately unlocks greater precision.


Key Takeaways

  • 3n + 4p = 7.80 models combined costs of two items.
  • Solving for p or n helps explore trade-offs in purchasing or planning.
  • The equation supports budgeting, business analysis, and economic modeling.
  • Integer solutions require careful testing or scaling to eliminate decimals.

Keywords: 3n + 4p = 7.80, linear equation, algebra, cost calculation, budgeting, cost analysis, integer solutions, household budget, economics equation.

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