2(x+1) + 3x = x(x+1)

Solving the Equation: 2(x + 1) + 3x = x(x + 1) – A Comprehensive Guide
When faced with algebraic equations, simplifying both sides and solving for the variable can sometimes seem challenging. One common equation that students and math enthusiasts often explore is: 2(x + 1) + 3x = x(x + 1)
This equation represents a powerful exercise in algebraic manipulation and problem-solving. In this SEO-optimized article, we break down the full process of solving 2(x + 1) + 3x = x(x + 1), providing clear steps, real-world applications, and useful keywords to help improve search visibility for educators and learners alike.
Understanding the Equation
The equation 2(x + 1) + 3x = x(x + 1) contains both linear and quadratic components. The left side involves distribution and combination of like terms, while the right side expands into a polynomial. Solving this equation helps reinforce skills in:
- Distributing parentheses
- Combining like terms
- Expanding binomials
- Solving first-degree and quadratic equations
Step-by-Step Solution
Step 1: Expand Both Sides
Start by expanding each term using algebraic properties.
Left-hand side (LHS): 2(x + 1) + 3x = 2·x + 2·1 + 3x = 2x + 2 + 3x = (2x + 3x) + 2 = 5x + 2
Right-hand side (RHS): x(x + 1) = x·x + x·1 = x² + x
So the equation becomes: 5x + 2 = x² + x
Step 2: Move All Terms to One Side
To solve for x, bring all terms to one side to form a standard quadratic equation: x² + x – 5x – 2 = 0 → x² – 4x – 2 = 0
Step 3: Solve the Quadratic Equation
Use the quadratic formula: x = [−b ± √(b² – 4ac)] / (2a) For x² – 4x – 2 = 0, a = 1, b = –4, c = –2
Calculate the discriminant: Δ = b² – 4ac = (−4)² – 4(1)(–2) = 16 + 8 = 24
Roots: x = [4 ± √24] / 2 √24 = √(4×6) = 2√6, so x = [4 ± 2√6] / 2 → x = 2 ± √6
Final Answer
The solutions are: x = 2 + √6 and x = 2 − √6
These are real, irrational roots confirming a valid quadratic solution.
Why This Equation Matters (Applications)
This type of equation models real-world phenomena such as:
- Financial break-even analysis, where costs and revenue interact nonlinearly
- Physics problems involving motion with variable acceleration
- Optimization scenarios in economics and engineering
Mastering its solution strengthens algebraic intuition critical for STEM fields.
Tips for Mastering Similar Problems
- Practice factoring and expanding – fluency reduces errors.
- Always simplify fully before solving.
- Double-check each step—small mistakes change outcomes.
- Use online algebra tools or graphing calculators to verify, but manual solving ensures deeper understanding.
Key SEO Keywords to Target
Optimize your content with these high-impact keywords and phrases:
- Solve 2(x + 1) + 3x = x(x + 1)
- Step-by-step quadratic equation solution
- Solve rational and irrational roots
- Algebra 2 equation solving techniques
- First-degree and second-degree equations
- Learn to balance algebra terms
- Real-world applications of quadratic equations
Conclusion
The equation 2(x + 1) + 3x = x(x + 1) is a prime example of how combining linear and quadratic expressions challenges students to apply fundamental algebraic principles. By following structured steps—expanding, simplifying, rearranging, and applying the quadratic formula—learners gain not just answers, but powerful analytical skills. Whether for homework, exams, or personal growth, mastering such equations opens doors in mathematics and beyond.
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