2(3) + 3d = 15 \implies 6 + 3d = 15 \implies 3d = 9 \implies d = 3

["# Understanding the Equation: 2(3) + 3d = 15 and How It Solves to d = 3", "Solving simple algebraic equations is a foundational skill in mathematics, and sometimes clarity in step-by-step reasoning makes all the difference. Let’s explore the step-by-step solution to the equation 2(3) + 3d = 15, leading to the conclusion that d = 3.", "## Step 1: Simplify the Expression on the Left Side", "We begin with the original equation:\n[\n2(3) + 3d = 15\n]", "First, simplify the multiplication inside the parentheses:\n[\n2 \ imes 3 = 6\n]", "So the equation becomes:\n[\n6 + 3d = 15\n]", "## Step 2: Isolate the Variable Term", "To solve for (d), subtract 6 from both sides to eliminate the constant term:\n[\n6 + 3d - 6 = 15 - 6\n]", "This simplifies to:\n[\n3d = 9\n]", "## Step 3: Solve for (d)", "Next, divide both sides by 3 to isolate (d):\n[\n\frac{3d}{3} = \frac{9}{3}\n]", "Which gives:\n[\nd = 3\n]", "## Conclusion", "The solution to the equation 2(3) + 3d = 15 clearly demonstrates how breaking down each step—simplifying expressions, isolating variables, and performing inverse operations—leads logically to the answer:\n[\n\boxed{d = 3}\n]", "This method not only solves the problem but also builds essential algebraic skills useful in more complex equations. Understanding each transformation step-by-step enhances mathematical fluency and confidence in working with linear expressions."]