#### -0.239
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- = \frac{\pi}{9} (6)^2 \frac{dh}{dt} = \frac{\pi}{9} \times 36 \times \frac{dh}{dt} = 4\pi \frac{dh}{dt}
- Solve:
- \frac{dh}{dt} = \frac{-3}{4\pi} \approx -0.239 \text{ m/min}
- A satellite orbits Earth in a circular path of radius 7,000 km with a period of 100 minutes. Calculate its linear speed in km/s.
- Circumference of orbit:
- C = 2\pi r = 2\pi \times 7000 \approx 43982.3 \text{ km}
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