\(0.1 \times 50 = 0.05 \times V_2\)

["Solving ( 0.1 \ imes 50 = 0.05 \ imes V_2 ): A Clear Step-by-Step Guide", "Understanding how to solve simple algebraic equations is essential for mastering algebra. One common type involves solving for an unknown variable when both sides of the equation contain coefficients and variables. In this article, we’ll walk through how to solve the equation:", "[\n0.1 \ imes 50 = 0.05 \ imes V_2\n]", "### Step 1: Simplify the Left Side", "Start by simplifying the left-hand side of the equation:", "[\n0.1 \ imes 50 = 5\n]", "So the equation becomes:", "[\n5 = 0.05 \ imes V_2\n]", "### Step 2: Isolate the Variable (V_2)", "To solve for (V_2), divide both sides of the equation by 0.05:", "[\nV_2 = \frac{5}{0.05}\n]", "### Step 3: Perform the Division", "Divide 5 by 0.05. To eliminate the decimal, multiply numerator and denominator by 100:", "[\nV_2 = \frac{5 \ imes 100}{0.05 \ imes 100} = \frac{500}{5} = 100\n]", "### Final Answer", "[\nV_2 = 100\n]", "### Why This Equation Matters", "This simple equation demonstrates how multiplying scalars by an unknown variable and balancing both sides leads to solving for unknowns—skills crucial in school math, finance, engineering, and science contexts.", "### Summary", "- ( 0.1 \ imes 50 = 5 )\n- The equation simplifies to ( 5 = 0.05 \ imes V_2 )\n- Dividing both sides by 0.05 yields ( V_2 = 100 )", "If you're learning algebra, practicing equations like this helps build strong problem-solving skills. Always simplify coefficients, isolate the variable, and verify your answer—simple steps for clear results!", "---", "Keywords:\nalgebra, solve equation, (0.1 \ imes 50 = 0.05 \ imes V_2), solving for variable, step-by-step math, algebraic equations, math tutorial, math explanation, solving linear equations, (V_2) solution", "Meta Description:\nLearn how to solve (0.1 \ imes 50 = 0.05 \ imes V_2) step-by-step. Understand the process of simplification, isolation, and calculation to find (V_2 = 100). Perfect for algebra beginners."]