\[ h(x^2 + 2) = x^4 + 4x^2 + 4 + 4x^2 + 8 + 3 \]
![\[ h(x^2 + 2) = x^4 + 4x^2 + 4 + 4x^2 + 8 + 3 \]](https://soloferat.biz.id/images/-hx2--2--x4--4x2--4--4x2--8--3-.jpg)
["Optimizing the Function: Simplifying and Solving ( h(x^2 + 2) = x^4 + 4x^2 + 4 + 4x^2 + 8 + 3 )", "Understanding and simplifying complex functions is essential in algebra and calculus, especially when dealing with composite functions like ( h(x^2 + 2) ). In this article, we’ll carefully analyze and simplify the given equation:", "[\nh(x^2 + 2) = x^4 + 4x^2 + 4 + 4x^2 + 8 + 3\n]", "---", "### Step 1: Combine Like Terms on the Right-Hand Side", "Start by combining all polynomial terms on the right-hand side:", "- ( x^4 ) appears once: ( x^4 )\n- ( x^2 ) terms: ( 4x^2 + 4x^2 = 8x^2 )\n- Constants: ( 4 + 8 + 3 = 15 )", "So,", "[\nh(x^2 + 2) = x^4 + 8x^2 + 15\n]", "---", "### Step 2: Rewrite the Argument of ( h )", "Let ( u = x^2 + 2 ). Then express ( h(u) ) in terms of ( u ):", "We know:", "[\nu = x^2 + 2 \quad \Rightarrow \quad x^2 = u - 2\n]", "Now compute ( x^4 ):", "[\nx^4 = (x^2)^2 = (u - 2)^2 = u^2 - 4u + 4\n]", "Substitute ( x^4 ) and ( x^2 ) into the expression for ( h(u) ):", "[\nh(u) = x^4 + 8x^2 + 15 = (u^2 - 4u + 4) + 8(u - 2) + 15\n]", "---", "### Step 3: Simplify the Expression in Terms of ( u )", "Expand and combine:", "[\nh(u) = u^2 - 4u + 4 + 8u - 16 + 15\n]", "Combine like terms:", "- ( u^2 ) remains: ( u^2 )\n- ( u ) terms: ( -4u + 8u = 4u )\n- Constants: ( 4 - 16 + 15 = 3 )", "Thus,", "[\nh(u) = u^2 + 4u + 3\n]", "---", "### Step 4: Return to the Original Variable", "Since ( u = x^2 + 2 ), the function becomes:", "[\nh(x^2 + 2) = (x^2 + 2)^2 + 4(x^2 + 2) + 3\n]", "But more importantly, we now have a simplified closed-form expression:", "[\nh(t) = t^2 + 4t + 3\n]", "where ( t = x^2 + 2 ).", "---", "### Why Simplify ( h(x^2 + 2) )?", "Simplifying composite functions like ( h(x^2 + 2) ) enables deeper insight into the function’s behavior, supports differentiation and integration, and facilitates solving equations such as ( h(t) = k ) for specific values. The final simplified form ( h(t) = t^2 + 4t + 3 ) is easier to work with in calculus, graphing, and further algebraic manipulation.", "---", "### Final Thoughts", "Working with composite functions can appear daunting at first, but breaking down expressions step-by-step reveals elegant solutions. By combining like terms, substituting arguments, and simplifying, we transformed a complex input-output relationship into a clean quadratic form:", "[\n\boxed{h(x^2 + 2) = x^4 + 8x^2 + 15 = (x^2 + 2)^2 + 4(x^2 + 2) + 3 = (x^2 + 2)^2 + 4(x^2 + 2) + 3}\n]", "Understanding such transformations is key to mastering higher-level mathematics and tackle more complex functions with confidence.", "---", "Keywords: ( h(x^2 + 2) ), simplify function, algebraic simplification, composite functions, ( h(t) = t^2 + 4t + 3 ), polynomial expressions, function transformation, calculus preparation", "Meta Description: Learn how to simplify and interpret the composite function ( h(x^2 + 2) = x^4 + 4x^2 + 4 + 4x^2 + 8 + 3 ) via step-by-step algebraic transformation to understand ( h(t) = t^2 + 4t + 3 )."]









